7+6t+3t^2=4

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Solution for 7+6t+3t^2=4 equation: 



7+6t+3t^2=4

We move all terms to the left:

7+6t+3t^2-(4)=0

We add all the numbers together, and all the variables

3t^2+6t+3=0

a = 3; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-6}{6}=-1$

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